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  #19 (permalink)  
Old Feb 15th, 2003, 11:53 AM
Keith's Avatar
Keith
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Join Date: Aug 2001
Location: SW Florida
Posts: 679
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Here is a different (and maybe simpler) way of getting to the same answer...

If the weight of the wheel acts as though it was all lumped at a radius of 9", then the rotational energy is the same as if the wheel was moving in a straight line at the speed of a point 9" from the center.

If the wheel radius is 12", then this speed is 9/12 = 75% of the speed of the vehicle.

As energy is proportial to speed squared, the rotational energy of the wheel is 56% (75% x 75%) of the linear energy. i.e. A 1 lb saving from the wheel is equivalent to a 1.56 lb saving from the car.

2007 DS/W MCS LSD, sport suspension, Enkei RPM2 wheels
2002 EB/W MCS Sport package, Rogue intake, Borla exhaust, 15% pulley & Madness sway bar
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